Hello,
We have a RUT906 here and we would like to use the I/O relay to light a 12V DC LED.
But to be sure that we do not destroy the router, do we need to connect an external power supply (+ DC) to the Common pin 5 and our LED to pin 10 or how should C and NO be connected?
Kind regards
Wim
Hi…
Have you checked here?
https://wiki.teltonika-networks.com/view/RUT906_Input/Output
Maybe you need to build a small circuit to better do what you want…
sample…
Hello,
I already looked at that page, but it’s not clear enough, there is also not an example on the page. It says for pin 5: “Relay Output (COM) (External 0-24 VDC or 0-40 VAC)”. Even though it says output i think i need to power the common pin, but i want to be sure before i give it power and the motherboard gets broken.
Hi…
The I/I port only have around 300mA.
So… you need a “auxiliary circuit”.
" An auxiliary circuit is a circuit that controls, measures, signals, or regulates a main circuit. It is made up of an electrical or mechanical accessory and its wiring. "
Because this… you need a “extra circuit” to increase the power of the I/O ports.
Sample…
So… the I/O just will power up the Q1 and the Q1 will power up the relay… The relay can be connect at 12VDC/120VAC.
and… the I/O will be protect.
Hello,
That is for 1-4 and 6-9, those are input/output? But it says 5 and 10 are for a relay, like a switch for turning on/off the light in a room. So you can connect a device to these pins and control the power to it with the router? Or isn’t that the purpose of these contacts?
You want to use * C & NO - Common and Normally Open contacts of the internal Non-Latching Relay respectively.
Maximum relay ratings: 4 A at 24 VDC, 4 A at 40 VAC. ?
Yes… You need to follow your picture to connect the device at RUT.
Hello,
I tested it and it works fine, just wanted to be sure.
Thank you
This topic was automatically closed 2 days after the last reply. New replies are no longer allowed.