Poe power for RUTX

Can you tell me the exact model of the poe power supply for RUTX11 and RUTX12? The PWR connection fails on both and I need to power them over POE for security.
Another question. Do you plan to release a model like the RUTX12 in 5G?
Thank you


Firstly, Welcome to the community, We’re glad you’re here.

Regarding POE, RUTX11 and RUTX12 are the routers that supports Passive Power over Ethernet (PoE) functionality on LAN port 1.

(Do not use in other ports!)

In simple terms, Active PoE refers to any type of PoE that negotiates the power between the switch and the PoE-powered device (RUTX device). Passive PoE does no such negotiation the power.


The appropriate PoE power supply might depend on factors such as the power requirements of your RUTX11 and RUTX12 model, the intended usage scenario, and any specific voltage and power rating requirements. any power supply should do as long as it meets the requirements described in the article.RUTX12 Powering Options - Teltonika Networks Wiki

Device PoE (passive) power- 9 - 30 VDC

Device Power consumption - Idle: < 4 W, Max: < 22 W

The device is NOT COMPLIANT with the IEEE 802.3at standard: it cannot power other devices over Ethernet.
The device is NOT COMPLIANT with the IEEE 802.3af-2003 standard which means powering the device from an IEEE 802.3af-2003 power supply will damage the device as it is not rated for input voltages of the PoE standard.

For your Additional information, The device can be powered from the power socket and over Ethernet simultaneously. The power socket has higher priority meaning that the device will draw power from the power socket as long as it is available.

When the device is switching from one power source to another it loses power for a fraction of a second and may reboot. The device will function correctly after the reboot.

Regarding your second question of the 5g device. currently, a 5G device with two modem modules is not on our road map and the only two available 5G devices are RUTX50 and TRB500.

If you would have any other questions, please feel free to ask.

Best Regards,

Nirup Singh

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Thank you very much for your explanation.

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